Type Challenges Judge

Promise.all

提出詳細

declare function PromiseAll<T extends any[]>(values: readonly [...T]): Promise<{ [P in keyof T]: T[P] extends PromiseLike<infer R> ? R : T[P] }>
提出日時2023-08-09 09:15:50
問題Promise.all
ユーザーookkoouu
ステータスWrong Answer
テストケース
import type { Equal, Expect } from '@type-challenges/utils' const promiseAllTest1 = PromiseAll([1, 2, 3] as const) const promiseAllTest2 = PromiseAll([1, 2, Promise.resolve(3)] as const) const promiseAllTest3 = PromiseAll([1, 2, Promise.resolve(3)]) type cases = [ Expect<Equal<typeof promiseAllTest1, Promise<[1, 2, 3]>>>, Expect<Equal<typeof promiseAllTest2, Promise<[1, 2, number]>>>, Expect<Equal<typeof promiseAllTest3, Promise<[number, number, number]>>>, ]