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Currying 1

提出詳細

type Currying<T> = T extends (...args: infer A) => infer Ret
  ? A extends [infer First, ...infer Rest]
    ? (arg: First) => Currying<(...args: Rest) => Ret>
    : Ret
  : T

declare function Currying<T>(fn: T): Currying<T>
提出日時2023-08-13 10:09:43
問題Currying 1
ユーザーtekihei2317
ステータスAccepted
テストケース
import type { Equal, Expect } from '@type-challenges/utils'

const curried1 = Currying((a: string, b: number, c: boolean) => true)
const curried2 = Currying((a: string, b: number, c: boolean, d: boolean, e: boolean, f: string, g: boolean) => true)

type cases = [
  Expect<Equal<
    typeof curried1, (a: string) => (b: number) => (c: boolean) => true
  >>,
  Expect<Equal<
    typeof curried2, (a: string) => (b: number) => (c: boolean) => (d: boolean) => (e: boolean) => (f: string) => (g: boolean) => true
  >>,
]